我就廢話不多說了，直接上代碼吧！

def sum_numbers(num): # 1.出口 if num == 1: return 1 # 2.數(shù)組累加 temp = sum_numbers(num - 1) return num + tempresult = sum_numbers(3)print(result)

輸出：

6

補(bǔ)充拓展：python遞歸計數(shù)及結(jié)束遞歸

題目：搜索旋轉(zhuǎn)排序數(shù)組

class Solution: TOTAL = 0 RUN = True def search(self, nums: List[int], target: int) -> int: # 將數(shù)組一分為二，分別比頭尾，尾大于頭為有序，剩下的為無序 i, j = 0, len(nums) - 1 res = -1 if nums and self.RUN: in_middle = (j + i) // 2 list1 = nums[:in_middle + 1] list2 = nums[in_middle + 1:] if nums[in_middle] >= nums[i]:res = self.binarySearch(list1, target)if res == -1: self.TOTAL += in_middle + 1 self.search(list2, target)else: self.TOTAL += res else:res = self.binarySearch(list2, target)if res == -1: self.search(list1, target)else: self.TOTAL += in_middle + 1 + res if not self.RUN: return self.TOTAL return res def binarySearch(self, nums, target): ''' 二分查找 ''' i, j = 0, len(nums) - 1 while i <= j: in_middle = (j + i) // 2 if nums[in_middle] == target:# print(nums, TOTAL)self.RUN = Falsereturn in_middle elif nums[in_middle] < target:i = in_middle + 1 else:j = in_middle - 1 return -1

以上這篇Python遞歸調(diào)用實現(xiàn)數(shù)字累加的代碼就是小編分享給大家的全部內(nèi)容了，希望能給大家一個參考，也希望大家多多支持好吧啦網(wǎng)。