問題描述

How to remove the seperator line in footerLayout? I have a footerLayout below the listView, used to display the totalAmount as shown below. If I click the seperator line in footerLayout, my app crashed.

My MainActivity

AllAdapter obj = new AllAdapter(getApplication(), search, listview,imageView,text,button);footerLayout = (LinearLayout) getLayoutInflater().inflate(R.layout.under_listview, null);totalAmount = (TextView) footerLayout.findViewById(R.id.amount);

LogCat error

java.lang.IndexOutOfBoundsException: Invalid index 2, size is 2 at java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:251) at java.util.ArrayList.get(ArrayList.java:304) at com.example.tony.monthlyexpenses.adapter.AllAdapter.getItem(AllAdapter.java:61) at com.example.tony.monthlyexpenses.QuickExpenses$1.onItemClick(QuickExpenses.java:88) at android.widget.AdapterView.performItemClick(AdapterView.java:301)

The error pointed to listView onClickListener

listview.setOnItemClickListener(new AdapterView.OnItemClickListener() { public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {mClickedPosition = position;Expenses o = (Expenses) obj.getItem(position);String day = o.getDate(); }});

AllAdapter

public Expenses getItem(int position) {return search.get(position); }

The footerLayout is supposed to be displayed outside the listView, not inside. How can I get rid of this ?

I also have activity_main.xml, AllAdapter class, all_adapter.xml for ListView and also under_listview.xml for the footerLayout.

activity_main

AllAdapter

under_listview

How to move the footerLayout out from the ListView ?

I add android:footerpidersEnabled='false' now become like this

But still clickable !!!

誰知道問題出在哪？

footerLayout被按時如何不出現(xiàn)灰色？

問題解答

很簡單，但也很容易出錯的問題，加了footer后，你的listview item數(shù)量是3，但adapter的viewcount其實并沒有變成3，所以在你點擊footer時執(zhí)行的是obj.getItem(2)，肯定是數(shù)組越界異常了。對于添加了header或footer的listview，正確的取item方法應(yīng)該是

listview.setOnItemClickListener(new AdapterView.OnItemClickListener() { public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {Expenses o = (Expenses) listView.getAdapter().getItem(position);if(o != null){ mClickedPosition = position; //Expenses o = (Expenses) obj.getItem(position); String day = o.getDate();} }});

header或footer屬于AdapterView的子view，listView.getAdapter().getItem(position);能確保你取2的position時不越界，再做對象空判斷。

你不能使用setOnItemClickListener 來作為footview的點擊事件，我認為你應(yīng)該單獨的去設(shè)置例如 footview.setonClickListener(new OnClickListener{}); 祝你好運

你這個是數(shù)組下標越界了啊，你的數(shù)組size是2，所以對應(yīng)的下標只能是0和1，但是你在使用的時候用了2，錯誤顯示你有個無效的index 2，你自己找下第61行和第88行，看是否有地方調(diào)用了index是2的

將footerLayout移出listView的寫法是

listview.addFooterView(footerLayout, null, false);