問題描述

現(xiàn)在碰到這樣一個需求：有一個數(shù)組

$scope.items = [ {name:’a1’},{name:’a2’},{name:’a3’}....]

現(xiàn)在需要它輸出

<ul> <li>a1</li><li>a2</li><li>a3</li><li>a4</li><li>a5</li><li>a6</li><li>a7</li><li>a8</li><li>a9</li><li>a10</li> //10個</ul><ul> <li>a11</li><li>a12</li><li>a13</li><li>a14</li><li>a15</li><li>a16</li><li>a17</li><li>a18</li><li>a19</li><li>a20</li> //10個</ul><ul> <li>a21</li><li>a22</li>... //10個</ul>

我想用ng-repeat輸出，想出的方案是，先把數(shù)組 length 除以 10

$scope.n = Math.ceil ( items.length / 10 );

然后ng-repeat輸出 n 個 ul，再分別在ul里 ng-repeat 10個item。

那么問題來了，如何ng-repeat輸出n個ul？

<ul ng-repeat=' ...不會寫... '> <li ng-repeat = ' item in items | ...//如何過濾'>{{item.name}} </li></ul>

求問各路大神啦！

更新問題！感謝各位同行！

首先，css已經(jīng)不可動了，因為根據(jù)產(chǎn)品需求已經(jīng)寫好了樣式，并得到了每行需要10個li的結(jié)果?？吹紷zchq88 這位朋友的提醒以后，我立刻做了一維數(shù)組轉(zhuǎn)二維數(shù)組的過濾器，像@Chobits 同學(xué)那樣的。但是報錯。

Error: [$rootScope:infdig] 10 $digest() iterations reached. Aborting!

console.log() 會發(fā)現(xiàn)數(shù)組被執(zhí)行了N遍過濾器。google也沒有找到原因和解決方案。我猜測是，拆數(shù)組的時候，由于指引型數(shù)據(jù)，引發(fā)了重復(fù)臟檢查。實驗了angular.copy也失敗，現(xiàn)在正在找其他解決方案。再次感謝！期待有同學(xué)提出其他解決方案！

解決！最后一次更新：

因為產(chǎn)品中items實際的結(jié)構(gòu)是

$scope.group = [ {key:888,items:[ {name:’a1’},{name:’a2’},{name:’a3’}....,{name:’a13’}...//n多個] }, {key:999,items:[ {name:’a1’},{name:’a2’},{name:’a3’}....,{name:’a33’}...//n多個] }, ....]

繞開了html中加過濾器產(chǎn)生的重復(fù)臟檢查問題。根據(jù)@Chobits 提供的過濾器,在控制器里對group進行了過濾

group.forEach(function(items){ items.items = $filter(’group’)(items.items);})

然后再ng-repeat輸出，問題解決。

<p ng-repeat = 'input in group'> <ul ng-repeat='items in input.items'><li ng-repeat='item in items'> {{item.name}}</li> </ul></p>

prefect！thanks everyone！

問題解答

//http://stackoverflow.com/a/14463190/2586541app.filter(’group’, function () { return function (items, groupSize) {var groups = [], inner;for (var i = 0; i < items.length; i++) { if (i % groupSize === 0) {inner = [];groups.push(inner); } inner.push(items[i]);}return groups; };});

$scope.group = [ {key:1,items:[ {name:’a1’},{name:’a2’},{name:’a3’}....] }, {key:2,items:[ {name:’a1’},{name:’a2’},{name:’a3’}....] }, ....]

<ul ng-repeat='g in group track by g.key'> <li ng-repeat='item in g.items'>{{item.name}} </li></ul>回答2：

http://stackoverflow.com/questions/21644493/how-to-split-the-ng-repeat-data-with-three-columns-using-bootstrap

However, the most direct and just plainly simple way to get columns is to use CSS columns:是的 贊同這個排一下版 一行顯示幾個完全可以用css做 方法多的都懶得寫

為什么不直接把ITEMS用JS變成2維數(shù)組？然后輸出？

把數(shù)據(jù)整理成樹形結(jié)構(gòu)即可。。。比如

scope.list = [{name:'a',children:[ {name:’son1 of a’}, {name:’son2 of a’} ]},{name:'b',children:[ {name:’son1 of b’}, {name:’son2 of b’} ]}]

然后ng里用雙層repeat

<ul ng-repeat='item in list'> <li ng-repeat = ' son in item.children'>{{son.name}} </li></ul>